求帮忙修改
时间:2011-12-11
来源:互联网
#include <iostream>
using namespace std;
class Complex
{
public:
Complex()
{real = 0; imag = 0;}
Complex(double r, double i)
{ real = r; imag = i;}
Complex operator + (Complex &c2);
Complex operator - (Complex &c2);
void display();
private:
double real;
double imag;
};
Complex Complex::operator +(Complex &c2)
{ Complex c;
c.real = real + c2.real;
c.imag = imag + c2.imag;
return c;}
Complex Complex::operator - (Complex &c2)
{
Complex c;
c.real = real - c2.real;
c.imag = imag - c2.imag;
return c;
}
void Complex::display()
{ cout<< "(" << real << "," << imag << "i)" <<endl;
}
int main()
{ Complex c1(3, 4), c2(5, -10), c3;
c3 = c1 + c2;
cout << "c1 + c2 = ";
c3.display();
c3 = c1 - c2;
cout << "c1 - c2 = ";
c3.display();
return 0;
}
我想改成数据是自己输入而不是固定的。
如何使用cin啊。
using namespace std;
class Complex
{
public:
Complex()
{real = 0; imag = 0;}
Complex(double r, double i)
{ real = r; imag = i;}
Complex operator + (Complex &c2);
Complex operator - (Complex &c2);
void display();
private:
double real;
double imag;
};
Complex Complex::operator +(Complex &c2)
{ Complex c;
c.real = real + c2.real;
c.imag = imag + c2.imag;
return c;}
Complex Complex::operator - (Complex &c2)
{
Complex c;
c.real = real - c2.real;
c.imag = imag - c2.imag;
return c;
}
void Complex::display()
{ cout<< "(" << real << "," << imag << "i)" <<endl;
}
int main()
{ Complex c1(3, 4), c2(5, -10), c3;
c3 = c1 + c2;
cout << "c1 + c2 = ";
c3.display();
c3 = c1 - c2;
cout << "c1 - c2 = ";
c3.display();
return 0;
}
我想改成数据是自己输入而不是固定的。
如何使用cin啊。
作者: youzhibc 发布时间: 2011-12-11
C++的STL本身就有complex类的
C/C++ code
输入:
(3,4) (5,-10)
输出
c1 + c2 = (8,-6)
c1 - c2 = (-2,14)
C/C++ code
#include <iostream> #include <complex> using namespace std; int main() { complex<double> c1, c2, c3; cin >> c1 >> c2; c3 = c1 + c2; cout << "c1 + c2 = "; cout << c3 << endl; c3 = c1 - c2; cout << "c1 - c2 = "; cout << c3 << endl; return 0; }
输入:
(3,4) (5,-10)
输出
c1 + c2 = (8,-6)
c1 - c2 = (-2,14)
作者: keiy 发布时间: 2011-12-11
实数部分和序数部分分开输入就好了,如
C/C++ code
C/C++ code
int x,y; cin>>x>>y;
作者: mscf 发布时间: 2011-12-11
谢谢,不过你这改变了我原本的结构了哇。 我必须用到构造函数的。
我想要的是针对这个代码,加一步能cin r i的。
我想要的是针对这个代码,加一步能cin r i的。
引用 1 楼 keiy 的回复:
C++的STL本身就有complex类的
C/C++ code
#include <iostream>
#include <complex>
using namespace std;
int main()
{
complex<double> c1, c2, c3;
cin >> c1 >> c2;
c3 = c1 + c2;
cout << "c1 + c2 = ";
cout << ……
C++的STL本身就有complex类的
C/C++ code
#include <iostream>
#include <complex>
using namespace std;
int main()
{
complex<double> c1, c2, c3;
cin >> c1 >> c2;
c3 = c1 + c2;
cout << "c1 + c2 = ";
cout << ……
作者: youzhibc 发布时间: 2011-12-11
能具体点么,
引用 2 楼 mscf 的回复:
实数部分和序数部分分开输入就好了,如
C/C++ code
int x,y;
cin>>x>>y;
实数部分和序数部分分开输入就好了,如
C/C++ code
int x,y;
cin>>x>>y;
作者: youzhibc 发布时间: 2011-12-11
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