asp正则表达式遍历的问题。
时间:2011-08-15
来源:互联网
<%
dim a
a="<b>我</b><b>你</b>"
set re = new RegExp
re.IgnoreCase = true
re.Global = true
re.pattern = "<b>(.[^<]*)</b>"
body = re.replace(a,"$1")
response.write body
response.write "</br>"
Set regEx = New RegExp
regEx.Pattern = "<b>(.[^<]*)</b>"
regEx.IgnoreCase = true
regEx.Global = true
Set Matches = regEx.Execute(a)
For Each Match in Matches
response.write Match.value '怎么获取$1
Next
%>
dim a
a="<b>我</b><b>你</b>"
set re = new RegExp
re.IgnoreCase = true
re.Global = true
re.pattern = "<b>(.[^<]*)</b>"
body = re.replace(a,"$1")
response.write body
response.write "</br>"
Set regEx = New RegExp
regEx.Pattern = "<b>(.[^<]*)</b>"
regEx.IgnoreCase = true
regEx.Global = true
Set Matches = regEx.Execute(a)
For Each Match in Matches
response.write Match.value '怎么获取$1
Next
%>
作者: wangpengbinqq 发布时间: 2011-08-15
For Each Match in Matches ' 遍历 Matches 集合。
RetStr = RetStr & Match.FirstIndex & "。
RetStr = RetStr & Match.Length &" "
RetStr = RetStr & Matches(0) &" " '
RetStr = RetStr & Matches(1)&" " '
RetStr = RetStr & Match.value&" " '
RetStr = RetStr & vbCRLF
Next
当然也可以使用
Matches.SubMatches(1)不使用遍历
RetStr = RetStr & Match.FirstIndex & "。
RetStr = RetStr & Match.Length &" "
RetStr = RetStr & Matches(0) &" " '
RetStr = RetStr & Matches(1)&" " '
RetStr = RetStr & Match.value&" " '
RetStr = RetStr & vbCRLF
Next
当然也可以使用
Matches.SubMatches(1)不使用遍历
作者: chinmo 发布时间: 2011-08-15
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