看下这段汇编是怎么走的吧...

我把它塞到CPU里面去然后它走到3jal那一条指令然后跳到18再回到0如此循环往复...中间那一大段都没走到...我猜这是个杯具...可是我还没学过汇编Orz...于是我想问一问这段指令正确的走法应该是什么样的...谢谢~

 0 : 3c010000; % (00) main: lui $1, 0 # address of data[0] %
 1 : 34240050; % (04) ori $4, $1, 80 # address of data[0] %
 2 : 20050004; % (08) addi $5, $0, 4 # counter %
 3 : 0c000018; % (0c) call: jal sum # call function %
 4 : ac820000; % (10) sw $2, 0($4) # store result %
 5 : 8c890000; % (14) lw $9, 0($4) # check sw %
 6 : 01244022; % (18) sub $8, $9, $4 # sub: $8 <- $9 - $4 %
 7 : 20050003; % (1c) addi $5, $0, 3 # counter %
 8 : 20a5ffff; % (20) loop2: addi $5, $5, -1 # counter - 1 %
 9 : 34a8ffff; % (24) ori $8, $5, 0xffff # zero-extend: 0000ffff %
 A : 39085555; % (28) xori $8, $8, 0x5555 # zero-extend: 0000aaaa %
 B : 2009ffff; % (2c) addi $9, $0, -1 # sign-extend: ffffffff %
 C : 312affff; % (30) andi $10, $9, 0xffff # zero-extend: 0000ffff %
 D : 01493025; % (34) or $6, $10, $9 # or: ffffffff %
 E : 01494026; % (38) xor $8, $10, $9 # xor: ffff0000 %
 F : 01463824; % (3c) and $7, $10, $6 # and: 0000ffff %
10 : 10a00001; % (40) beq $5, $0, shift # if $5 = 0, goto shift %
11 : 08000008; % (44) j loop2 # jump loop2 %
12 : 2005ffff; % (48) shift: addi $5, $0, -1 # $5 = ffffffff %
13 : 000543c0; % (4c) sll $8, $5, 15 # <<15 = ffff8000 %
14 : 00084400; % (50) sll $8, $8, 16 # <<16 = 80000000 %
15 : 00084403; % (54) sra $8, $8, 16 # >>16 = ffff8000 (arith) %
16 : 000843c2; % (58) srl $8, $8, 15 # >>15 = 0001ffff (logic) %
17 : 08000017; % (5c) finish: j finish # dead loop %
18 : 00004020; % (60) sum: add $8, $0, $0 # sum %
19 : 8c890000; % (64) loop: lw $9, 0($4) # load data %
1A : 20840004; % (68) addi $4, $4, 4 # address + 4 %
1B : 01094020; % (6c) add $8, $8, $9 # sum %
1C : 20a5ffff; % (70) addi $5, $5, -1 # counter - 1 %
1D : 14a0fffb; % (74) bne $5, $0, loop # finish? %
1E : 00081000; % (78) sll $2, $8, 0 # move result to $v0 %
1F : 03e00008; % (7c) jr $ra # return %

这叫什么汇编？