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XPath选择路径出错

时间:2009-04-21

来源:互联网

JS代码
<script src="jquery/jquery.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function(){
$('.#selected-plays>li').addClass('horizonta1');
$('.#selected-plays li:not(.horizonta1)').addClass('sub-level');
$('a[@href=^"mailto:"]').addClass('mailto');            这里想通过XPath获取  a href  里面 以 mailto:  开头  给于  mailtl  样式。错误提示:undefine 为空或不是对象  例外被抛出且未被接住。
});
</script>
页面代码
<ul id="selected-plays">
<li>Comedies
<ul>
<li><a href="http://www.mysite.com/asyoulikeit/">
As You Like It</a></li>
<li>All's Well That Ends Well</li>
<li>A Midsummer Night's Dream</li>
<li>Twelfth Night</li>
</ul>
</li>
<li>Tragedies
<ul>
<li><a href="hamlet.pdf">Hamlet</a></li>
<li>Macbeth</li>
<li>Romeo and Juliet</li>
</ul>
</li>
<li>Histories
<ul>
<li>Henry IV (<a href="mailto:[email protected]">email</a>)
<ul>
<li>Part I</li>
<li>Part II</li>
</ul>
<li><a href="http://www.shakespeare.co.uk/henryv.htm">
Henry V</a></li>
<li>Richard II</li>
</ul>
</li>
</ul>

作者: dwtmtdh   发布时间: 2009-04-21

jq 1.2以后就不默认支持xpath了

作者: shawphy   发布时间: 2009-04-22

哦,这样说,谢谢啊。看来我看的教程有点老了,有没有新一点的教程下载呀??

作者: dwtmtdh   发布时间: 2009-04-23