一个sql查询问题,实在没办法解决啊,只有50分了,麻烦帮帮忙····
时间:2011-12-27
来源:互联网


我要查询的结构如图:

上面截图已经简要的说明了我要查询的东西,但是我sql太差不知道怎么写...............
有两张表A表和B表 ,2张表存在主外建关系,图中能看到,
我现在要按照第二张图的查询,来查出我要的结果......
希望各位大哥大姐帮忙看看应该怎么写语句,,,,,,,,,
实在想不出来,就这么多分 不好意思了,,,,,,,,
作者: boqian_shi 发布时间: 2011-12-27
作者: yanyuchonglou 发布时间: 2011-12-27
该下班了,明天再看吧。
.......................................大哥晚上有时间给看看呗

作者: boqian_shi 发布时间: 2011-12-27
select name, (select count(*) from a where name=t.name)namecount, (select count(*) from a where newname=t.name)newnamecount, count(*) countName, (select count(*) from a innner join b on a.id=b.id and a.name=t.name and b.type=1)type1name, (select count(*) from a innner join b on a.id=b.id and a.newname=t.name and b.type=1)type1name, (select count(*) from b where type=1)counttype1, (select count(*) from a innner join b on a.id=b.id and a.name=t.name and b.type=0)type0name, (select count(*) from a innner join b on a.id=b.id and a.newname=t.name and b.type=0)type0name, (select count(*) from b where type=0)counttype0 from( select name from a union select newname from a )t
作者: qianjin036a 发布时间: 2011-12-27
作者: ssp2009 发布时间: 2011-12-27
作者: ssp2009 发布时间: 2011-12-27
countName=(select count(*) from a where name=t.name or newname=t.name)
大哥能给个全的吗

作者: boqian_shi 发布时间: 2011-12-27
select [name], (select count(*) from a where [name]=t.[name])namecount, (select count(*) from a where newname=t.[name])newnamecount, countName=(select count(*) from a where name=t.name or newname=t.name), (select count(*) from a innner join b on a.id=b.aid and a.[name]=t.[name] and b.[type]=1)type1name, (select count(*) from a innner join b on a.id=b.aid and a.newname=t.[name] and b.[type]=1)type1name, (select count(*) from b where [type]=1)counttype1, (select count(*) from a innner join b on a.id=b.aid and a.[name]=t.[name] and b.[type]=0)type0name, (select count(*) from a innner join b on a.id=b.aid and a.newname=t.[name] and b.[type]=0)type0name, (select count(*) from b where [type]=0)counttype0 from( select [name] from a union select newname from a )t
我大概修改了下 但是还不行么····
作者: boqian_shi 发布时间: 2011-12-27
select [name], (select count(*) from a where [name]=t.[name])namecount, (select count(*) from a where newname=t.[name])newnamecount, countName=(select count(*) from a where name=t.name or newname=t.name), (select count(*) from a innner join b on a.id=b.aid and a.[name]=t.[name] and b.[type]=1)type1name, (select count(*) from a innner join b on a.id=b.aid and a.newname=t.[name] and b.[type]=1)type1name, (select count(*) from b where [type]=1)counttype1, (select count(*) from a innner join b on a.id=b.aid and a.[name]=t.[name] and b.[type]=0)type0name, (select count(*) from a innner join b on a.id=b.aid and a.newname=t.[name] and b.[type]=0)type0name, (select count(*) from b where [type]=0)counttype0 from( select [name] from a union select newname from a )t
我大概修改了下 但是还不行啊········
作者: boqian_shi 发布时间: 2011-12-27
SQL code
create table a(id int,name varchar(10),newname varchar(10),prjname varchar(10)) insert into a select 1,'zs','ls','prj1' insert into a select 2,'zs','ww','prj2' insert into a select 3,'ls','ww','prj3' insert into a select 4,'ls','zs','prj4' insert into a select 5,'ww','zs','prj5' insert into a select 6,'zs','wmz','prj6' create table b(id int,aid int,type int) insert into b select 1,1,0 insert into b select 2,2,1 insert into b select 3,1,1 insert into b select 4,2,0 insert into b select 5,1,1 insert into b select 6,2,0 insert into b select 7,3,1 insert into b select 8,4,1 insert into b select 9,5,0 insert into b select 10,6,1 go select name, (select count(*) from a where name=t.name)namecount, (select count(*) from a where newname=t.name)newnamecount, (select count(*) from a where name=t.name)+(select count(*) from a where newname=t.name) countName, (select count(*) from a inner join b on a.id=b.aid and a.name=t.name and b.type=1)type1name, (select count(*) from a inner join b on a.id=b.aid and a.newname=t.name and b.type=1)type1newname, (select count(*) from a inner join b on a.id=b.aid and a.name=t.name and b.type=1)+ (select count(*) from a inner join b on a.id=b.aid and a.newname=t.name and b.type=1)counttype1, (select count(*) from a inner join b on a.id=b.aid and a.name=t.name and b.type=0)type0name, (select count(*) from a inner join b on a.id=b.aid and a.newname=t.name and b.type=0)type0name, (select count(*) from a inner join b on a.id=b.aid and a.name=t.name and b.type=0)+ (select count(*) from a inner join b on a.id=b.aid and a.newname=t.name and b.type=0)counttype0 from( select name from a union select newname from a )t group by name /* name namecount newnamecount countName type1name type1newname counttype1 type0name type0name counttype0 ---------- ----------- ------------ ----------- ----------- ------------ ----------- ----------- ----------- ----------- ls 2 1 3 2 2 4 0 1 1 wmz 0 1 1 0 1 1 0 0 0 ww 1 2 3 0 2 2 1 2 3 zs 3 2 5 4 1 5 3 1 4 (4 行受影响) */ go drop table a,b
作者: qianjin036a 发布时间: 2011-12-27
作者: ssp2009 发布时间: 2011-12-27

作者: boqian_shi 发布时间: 2011-12-27
哪里不对?
谢谢 好了····
作者: boqian_shi 发布时间: 2011-12-27
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