存储过程if问题
时间:2011-12-25
来源:互联网
ELSE IF (@prefix = 172) begin IF exists (select XAttack from [Item] WHERE IID = @iid AND XAttack < 5 ) UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid IF exists (select [Index], Num from [Item] WHERE IID = @iid AND [Index] = 3075 AND Num >0 ) UPDATE [Item] SET [Index] = [Index] , Num = Num + 1 WHERE IID = @iid else SET @IID = @IID +1 INSERT INTO Item ( [PID], [IID], [Index], [Prefix], [Info], [Num], [MaxEnd], [CurEnd], [SetGem], [XAttack], [XMagic], [XDefense], [XHit], [XDodge], [Protect], [UpgrLevel], [UpgrRate]) VALUES ( @PID, @IID, 3075, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ) end
如果XAttack =4 就执行UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid
如果XAttack =6 IF exists (select [Index], Num from [Item] WHERE IID = @iid AND [Index] = 3075 AND Num >0 )就执行UPDATE [Item] SET [Index] = [Index] , Num = Num + 1 WHERE IID = @iid
否则就执行 else
请大家帮忙指数下,我这个应该怎么写!高手帮下帮感谢。祝大家圣诞节快乐!
作者: zxc2015 发布时间: 2011-12-25
SQL code
ELSE IF (@prefix = 172) begin if XAttack =4 UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid else XAttack =6 and exists (select [Index], Num from [Item] WHERE IID = @iid AND [Index] = 3075 AND Num UPDATE [Item] SET [Index] = [Index] , Num = Num + 1 WHERE IID = @iid end else
作者: qianjin036a 发布时间: 2011-12-25
IF exists (select XAttack from [Item] WHERE IID = @iid AND XAttack < 5 ) UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid and XAttack =4 IF exists (select [Index], Num from [Item] WHERE IID = @iid AND [Index] = 3075 AND Num >0 ) UPDATE [Item] SET [Index] = [Index] , Num = Num + 1 WHERE IID = @iid and XAttack =6
作者: ssp2009 发布时间: 2011-12-25
SQL code
IF exists (select XAttack from [Item] WHERE IID = @iid AND XAttack < 5 )
UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid and XAttack =4
IF exists (select [Index], Num from ……
Num = Num + 1,怎么这个数据不加1呢?
作者: zxc2015 发布时间: 2011-12-25
begin if XAttack =4 UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid else XAttack =6 and exists (select [Index], Num from [Item] WHERE IID = @iid AND [Index] = 3075 AND Num UPDATE [Item] SET [Index] = [Index] , Num = Num + 1 WHERE IID = @iid end ..
作者: fredrickhu 发布时间: 2011-12-25
SQL code
begin
if XAttack =4
UPDATE [Item] SET XAttack = XAttack+1 WHERE IID = @iid
else XAttack =6 and exists (select [Index], Num from [Item] WHERE IID = @iid AND [Index] = 307……
消息 102,级别 15,状态 1,过程 SetPrefix,第 185 行
'XAttack' 附近有语法错误。
作者: zxc2015 发布时间: 2011-12-25
作者: zxc2015 发布时间: 2011-12-25
作者: zxc2015 发布时间: 2011-12-25
热门阅读
-
office 2019专业增强版最新2021版激活秘钥/序列号/激活码推荐 附激活工具
阅读:74
-
如何安装mysql8.0
阅读:31
-
Word快速设置标题样式步骤详解
阅读:28
-
20+道必知必会的Vue面试题(附答案解析)
阅读:37
-
HTML如何制作表单
阅读:22
-
百词斩可以改天数吗?当然可以,4个步骤轻松修改天数!
阅读:31
-
ET文件格式和XLS格式文件之间如何转化?
阅读:24
-
react和vue的区别及优缺点是什么
阅读:121
-
支付宝人脸识别如何关闭?
阅读:21
-
腾讯微云怎么修改照片或视频备份路径?
阅读:28