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json数据格式拼凑，数组合并，求助！

时间：2011-12-23

来源：互联网

有三个数组
$arr = array('张三','李四','王五');
$arr2 = array(100,200,300);
$arr3 = array(50,60,70);

如何平凑成另外一个数组$array，最后echo json_encode($array)输出如下格式

{"total":"3",
"result":[
{"date":"1","name":"张三","value":"100","other":"50"},
{"date":"1","name":"李四","value":"200","other":"60"},
{"date":"1","name":"王五","value":"300","other":"70"}
]
}

兄弟们，Help…

作者: zubin_hu 发布时间: 2011-12-23

该回复于2011-12-23 16:12:45被管理员删除

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ale1212
(ale1212)
等　级：

#2楼得分：0回复于：2011-12-23 16:23:51

<?php
$arr = array('张三','李四','王五');
$arr2 = array(100,200,300);
$arr3 = array(50,60,70);
$date=time();
$result['total']=sizeof($arr);
for($i=0;$i<sizeof($arr);$i++)
{

$result['result'][]=array("date"=>$date,"name"=>$arr[$i],"value"=>$arr2[$i],"other"=>$arr3[$i]);

}
echo json_encode($result);

/*
{"total":"3",
"result":[
{"date":"1","name":"张三","value":"100","other":"50"},
{"date":"1","name":"李四","value":"200","other":"60"},
{"date":"1","name":"王五","value":"300","other":"70"}
]
}
*/

?>

作者: ale1212 发布时间: 2011-12-23

json数据格式拼凑，数组合并，求助！

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