会Fortran的请进,程序有个小问题麻烦帮忙解决下。
时间:2011-12-21
来源:互联网
代码如下:
C/C++ code
出现问题如下:
error #6635: This actual argument must be the name of a procedure and not a data object. [DERIVS1]
1>compilation aborted for D:\scientific research\F1\F1.f90 (code 1)
C/C++ code
PROGRAM F1 ! Driver for routine RK4 ! EXTERNAL DERIVS1 ! USE DFlib PARAMETER(N=4) !USES BESSJ0,BESSJ1,BESSJ DIMENSION Y(N),DYDX(N),YOUT(N) X=1.0 Y(1)=BESJ0(X) Y(2)=BESJ1(X) Y(3)=BESJN(2,X) Y(4)=BESJN(3,X) DYDX(1)= -Y(2) DYDX(2)=Y(1)-Y(2) DYDX(3)=Y(2)-2.0*Y(3) DYDX(4)=Y(3)-3.0*Y(4) WRITE(*,'(/1X,A,T19,A,T31,A,T43,A,T55,A)')& 'Bessel Function:','J0','J1','J2','J3' DO I=1,5 H=0.2*I CALL RK4(Y,DYDX,N,X,H,YOUT,DERIVS1) WRITE(*,'(/1X,A,F6.2)')'For a step size of',H WRITE(*,'(1X,A10,4F12.6)')'RK4:',(YOUT(J),J=1,4) WRITE(8,'(1X,A10,4F12.6)')'Actual:',BESJ0(X+H)& ,BESJ1(X+H),BESJN(2,X+H),BESJN(3,X+H) END DO END PROGRAM SUBROUTINE DERIVS1(X,Y,DYDX) DIMENSION Y(1),DYDX(1) DYDX(1)=-Y(2) DYDX(2)=Y(1)-(1.0/X)*Y(2) DYDX(3)=Y(2)-(2.0/X)*Y(3) DYDX(4)=Y(3)-(3.0/X)*Y(4) END SUBROUTINE DERIVS1 SUBROUTINE RK4(y,dydx,n,x,h,yout,derivs) PARAMETER (nmax=10) DIMENSION y(n),dydx(n),yout(n),yt(nmax),dyt(nmax),& dym(nmax) REAL hh,h6,xh,x,h INTEGER i,n hh=h*0.5 h6=h/6. xh=x+hh do i=1,n yt(i)=y(i)+hh*dydx(i) end do call derivs(xh,yt,dyt) do i=1,n yt(i)=y(i)+hh*dyt(i) end do call derivs(xh,yt,dym) do i=1,n yt(i)=y(i)+h*dym(i) dym(i)=dyt(i)+dym(i) end do call derivs(x+h,yt,dyt) do i=1,n yout(i)=y(i)+h6*(dydx(i)+dyt(i)+2.*dym(i)) end do END SUBROUTINE RK4
出现问题如下:
error #6635: This actual argument must be the name of a procedure and not a data object. [DERIVS1]
1>compilation aborted for D:\scientific research\F1\F1.f90 (code 1)
作者: zzf8811 发布时间: 2011-12-21
你把subroutine当成function来用了
作者: xunxun1982 发布时间: 2011-12-21
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