取支付串数据问题

有一个支付串 是这样的string=‘12,12,34,34,5,5,5,6,7，’；可是我想得到里面的数据重复的只要其中一个如有两个12,12 我只得到一个12，就可以了。。。请高手帮忙。。。

拿出来 一个个比 再塞进去

void Main()
{
string str="12,12,34,34,5,5,5,6,7";
str=string.Join(",",str.Split(',').Distinct().ToArray());
Console.WriteLine(str); //12,34,5,6,7
}

C# code

string[] test = "1,5,9,12,14,7,12,11".Split(',');
Response.Write(String.Join(",", test.Distinct().ToArray()));

C# code

 string aa = "12,12,34,34,5,5,5,6,7";
        string[] words = aa.Split(new char[] { ',', ' ' });

        ArrayList ar = new ArrayList();
        for (int i = 0; i < words.Length; i++)
        {
            if (!ar.Contains(words[i]))
            {
                ar.Add(words[i]);
            }
        }
//ar 就是唯一出现的值的集合

C# code

string temp = string.Empty;
             StringBuilder newString = new StringBuilder();
             
             string str = "12,12,13,13,14,14";
             string[] array = str.Split(',');
           
               int i = 0;
               do
               {
                   if (i > 0)
                   {
                       if (array[i].Equals(temp))
                       {
                           newString.Append(array[i]);
                           if (i != array.Length - 1)
                               newString.Append(",");
                       
                       }
                   }
               
                   temp = array[i];
               
                   i++;
               }
               while (i < array.Length);

               Console.WriteLine(newString.ToString());
               Console.ReadKey();