无人问津的帖子又来了...

--> 测试数据：[获取表]
if object_id('[获取表]') is not null drop table [获取表]
create table [获取表]([卡号] int,[获取值] int,[年份] int,[月份] int)
insert [获取表]
select 1102,460,2010,11 union all
select 1102,230,2010,11 union all
select 1102,530,2010,11 union all
select 1102,265,2010,11 union all
select 1102,530,2010,11 union all
select 1102,230,2010,12 union all
select 1102,265,2010,12 union all
select 1102,530,2010,12 union all
select 1102,530,2010,12 union all
select 1102,230,2011,1 union all
select 1102,230,2011,1 union all
select 1102,460,2011,1 union all
select 1102,690,2011,1 union all
select 1102,1150,2011,1 union all
select 1102,1700,2011,1 union all
select 1102,265,2011,1 union all
select 1102,1325,2011,1 union all
select 1102,1325,2011,1 union all
select 1102,1060,2011,2 union all
select 1102,530,2011,3 union all
select 1102,530,2011,3 union all
select 1102,530,2011,4 union all
select 1102,795,2011,4 union all
select 1102,795,2011,4 union all
select 1102,530,2011,4 union all
select 1102,530,2011,5 union all
select 1102,530,2011,5 union all
select 1102,133,2011,5 union all
select 1102,266,2011,5 union all
select 1102,340,2011,9 union all
select 1102,340,2011,10 union all
select 1102,340,2011,10 union all
select 1102,680,2011,11


--> 测试数据：[兑换表]
if object_id('[兑换表]') is not null drop table [兑换表]
create table [兑换表]([卡号] int,[兑换值] int,[年份] int,[月份] int)
insert [兑换表]
select 1102,1920,2010,12 union all
select 1102,1512,2011,1 union all
select 1102,8550,2011,3 union all
select 1102,975,2011,4 union all
select 1102,3870,2011,9 union all
select 1102,430,2011,10 union all
select 1102,916,2011,11 union all
select 1102,550,2011,12


******
查询结果 
卡号 总获取 总兑换 剩余 年份 月份
1102 17174 12957 4217 2011 8
1102 17514 12957 4557 2011 9
1102 18194 16827 1367 2011 10

你怎么知道这帖子无人问津的?

SQL code

create table [获取表]([卡号] int,[获取值] int,[年份] int,[月份] int)
insert [获取表]
select 1102,460,2010,11 union all
select 1102,230,2010,11 union all
select 1102,530,2010,11 union all
select 1102,265,2010,11 union all
select 1102,530,2010,11 union all
select 1102,230,2010,12 union all
select 1102,265,2010,12 union all
select 1102,530,2010,12 union all
select 1102,530,2010,12 union all
select 1102,230,2011,1 union all
select 1102,230,2011,1 union all
select 1102,460,2011,1 union all
select 1102,690,2011,1 union all
select 1102,1150,2011,1 union all
select 1102,1700,2011,1 union all
select 1102,265,2011,1 union all
select 1102,1325,2011,1 union all
select 1102,1325,2011,1 union all
select 1102,1060,2011,2 union all
select 1102,530,2011,3 union all
select 1102,530,2011,3 union all
select 1102,530,2011,4 union all
select 1102,795,2011,4 union all
select 1102,795,2011,4 union all
select 1102,530,2011,4 union all
select 1102,530,2011,5 union all
select 1102,530,2011,5 union all
select 1102,133,2011,5 union all
select 1102,266,2011,5 union all
select 1102,340,2011,9 union all
select 1102,340,2011,10 union all
select 1102,340,2011,10 union all
select 1102,680,2011,11
create table [兑换表]([卡号] int,[兑换值] int,[年份] int,[月份] int)
insert [兑换表]
select 1102,1920,2010,12 union all
select 1102,1512,2011,1 union all
select 1102,8550,2011,3 union all
select 1102,975,2011,4 union all
select 1102,3870,2011,9 union all
select 1102,430,2011,10 union all
select 1102,916,2011,11 union all
select 1102,550,2011,12
go
select distinct 卡号,
(select sum(获取值) from 获取表 where 卡号=a.卡号 and (年份<a.年份 or (年份=a.年份 and 月份<=a.月份))) 总获取,
(select sum(兑换值) from 兑换表 where 卡号=a.卡号 and (年份<a.年份 or (年份=a.年份 and 月份<=a.月份))) 总兑换,
年份,月份 FROM (
select distinct 卡号,2011 as 年份,8 as 月份 from 获取表
union
select distinct 卡号,2011,9 from 获取表
union
select distinct 卡号,2011,10 from 获取表
)a
/*
卡号          总获取         总兑换         年份          月份
----------- ----------- ----------- ----------- -----------
1102        17174       12957       2011        8
1102        17514       16827       2011        9
1102        18194       17257       2011        10

(3 行受影响)

*/
go
drop table 兑换表,获取表

？？？？？？？？