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我想把查询的多条记录合为一条怎么办?

时间:2011-12-12

来源:互联网

例如:查询结果为
SQL code

MemberID      Name      Sex      Email          Interest
000001        张三       男      aaa@hao.com     打球
000001        张三       男      aaa@hao.com     游泳
000001        张三       男      bbb@hao.com     看电影


我想把这些记录何为一条,如:
SQL code

MemberID      Name      Sex      Email          Interest
000001        张三       男      aaa@hao.com     打球、游泳、看电影


怎么办?

作者: xp447196763   发布时间: 2011-12-12

上面写错了,邮箱都是[email protected]

作者: xp447196763   发布时间: 2011-12-12

SQL code

if object_id('tb') is not null
   drop table tb
go
create table tb
(
 MemberID varchar(10),
 Name varchar(10),
 Sex varchar(10),
 Email varchar(20),
 Interest varchar(10)
)
go
insert into tb
select '000001','张三','','[email protected]','打球' union all
select '000001','张三','','[email protected]','游泳' union all
select '000001','张三','','[email protected]','看电影'
go
select MemberID,Name=Max(Name),Sex=Max(Sex),Email=Max(Email),
 Interest=stuff((select ','+Interest from tb where MemberID=a.MemberID for xml path('')),1,1,'')
 from tb a group by MemberID
go
/*
MemberID   Name       Sex        Email                Interest
---------- ---------- ---------- -------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
000001     张三         男          [email protected]          打球,游泳,看电影

(1 行受影响)

*/

作者: pengxuan   发布时间: 2011-12-12

SQL code

--还是那个语句,数据变一下
if object_id('tb') is not null
   drop table tb
go
create table tb
(
 MemberID varchar(10),
 Name varchar(10),
 Sex varchar(10),
 Email varchar(20),
 Interest varchar(10)
)
go
insert into tb
select '000001','张三','','[email protected]','打球' union all
select '000001','张三','','[email protected]','游泳' union all
select '000001','张三','','[email protected]','看电影'
go
select MemberID,Name=Max(Name),Sex=Max(Sex),Email=Max(Email),
 Interest=stuff((select ','+Interest from tb where MemberID=a.MemberID for xml path('')),1,1,'')
 from tb a group by MemberID
go
/*
MemberID   Name       Sex        Email                Interest
---------- ---------- ---------- -------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
000001     张三         男          [email protected]          打球,游泳,看电影

(1 行受影响)

*/

作者: pengxuan   发布时间: 2011-12-12

不要发重复贴

作者: szstephenzhou   发布时间: 2011-12-12

重复贴

作者: q465897859   发布时间: 2011-12-12

SQL code

create table xp447196763
(MemberID varchar(8), name varchar(4), Sex varchar(4), Email varchar(15), Interest varchar(8))

insert into xp447196763
select '000001', '张三', '', '[email protected]', '打球' union all
select '000001', '张三', '', '[email protected]', '游泳' union all
select '000001', '张三', '', '[email protected]', '看电影'


declare @Interests varchar(50)=''
select @Interests=@Interests+Interest+''
from xp447196763

select MemberID,name,Sex,Email,
left(@Interests,len(@Interests)-1) Interest
from xp447196763
group by MemberID,name,Sex,Email

MemberID name Sex  Email           Interest
-------- ---- ---- --------------- --------------------------------------------------
000001   张三   男    aaa@hao.com     打球、游泳、看电影

(1 row(s) affected)

作者: ap0405140   发布时间: 2011-12-12

SQL code
合并列值 
--*******************************************************************************************
表结构,数据如下: 
id    value 
----- ------ 
1    aa 
1    bb 
2    aaa 
2    bbb 
2    ccc 

需要得到结果: 
id    values 
------ ----------- 
1      aa,bb 
2      aaa,bbb,ccc 
即:group by id, 求 value 的和(字符串相加) 

1. 旧的解决方法(在sql server 2000中只能用函数解决。) 
--=============================================================================
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
--1. 创建处理函数 
CREATE FUNCTION dbo.f_strUnite(@id int) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @str varchar(8000) 
    SET @str = '' 
    SELECT @str = @str + ',' + value FROM tb WHERE id=@id 
    RETURN STUFF(@str, 1, 1, '') 
END 
GO 
-- 调用函数 
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id 
drop table tb 
drop function dbo.f_strUnite 
go
/* 
id          value      
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
(所影响的行数为 2 行) 
*/ 
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
-- 查询处理 
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( 
        SELECT [values]= STUFF(REPLACE(REPLACE( 
            ( 
                SELECT value FROM tb N 
                WHERE id = A.id 
                FOR XML AUTO 
            ), ' <N value="', ','), '"/>', ''), 1, 1, '') 
)N 
drop table tb 

/* 
id          values 
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 行受影响) 
*/ 

--SQL2005中的方法2 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 

select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') 
from tb 
group by id 

/* 
id          values 
----------- -------------------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 row(s) affected) 

*/ 

作者: ssp2009   发布时间: 2011-12-12