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求助.关于大写数字转阿拉伯问题

时间：2011-12-11

来源：互联网

C# code


public  string UperNumberToLower(string srcStr)
        {

            srcStr = Regex.Replace(srcStr, @"(?<![零一二三四五六七八九])十", "一十");
            srcStr = Regex.Replace(srcStr, @"十(?![零一二三四五六七八九])", "十零");
            return Regex.Replace(srcStr, @"(?![千百])[零一二三四五六七八九十百千万]+", new MatchEvaluator(UpToLowerDelegate));
        }

        public  string UpToLowerDelegate(Match m)
        {
            string uNumber = m.Value;

            int total = 0;
            int unit = -1;
            int standNum = -1;

            List<string> listNum = new List<string>(new string[] { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九" });
            List<string> listUnit = new List<string>(new string[] { "十", "百", "千","万" });
            List<int> listInt = new List<int>(new int[] { 10, 100, 1000, 10000 });

            for (int i = 0; i < uNumber.Length; i++)
            {
                string strChar = uNumber[i].ToString();
                if (listNum.IndexOf(strChar) > -1)
                {
                    standNum = listNum.IndexOf(strChar);
                }

                if (listUnit.IndexOf(strChar) > -1)
                {
                    if (listUnit.IndexOf(strChar) < unit)
                    {
                        total = total + standNum * listInt[listUnit.IndexOf(strChar)];
                    }
                    else
                    {
                        total = (total + standNum) * listInt[listUnit.IndexOf(strChar)];
                        unit = listUnit.IndexOf(strChar);
                    }
                    standNum = -1;

                }
                if (i == uNumber.Length - 1 && standNum != -1)
                {
                    total = total + standNum;
                }

            }

            return total.ToString();
        }