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求sql函数判断一个字符串里的字符有没有在另一个字符串里出现过

时间：2011-12-06

来源：互联网

如题：比如A='1,2,3,4';B='1,4,6,7';这说明A中有字符串(1和4)在B中出现过。

作者: xiaoyuan402 发布时间: 2011-12-06

先把A拆分，再在B用CHARINDEX判断

拆分的写法论坛很多，自己找找或者等楼下

作者: Haiwer 发布时间: 2011-12-06

SQL code

--参考
拆分表:

--> --> (Roy)生成測試數據
 
if not object_id('Tab') is null
    drop table Tab
Go
Create table Tab([Col1] int,[COl2] nvarchar(5))
Insert Tab
select 1,N'a,b,c' union all
select 2,N'd,e' union all
select 3,N'f'
Go

--SQL2000用辅助表:
if object_id('Tempdb..#Num') is not null
    drop table #Num
go
select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
Select 
    a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) 
from 
    Tab a,#Num b
where
    charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
--2000不使用辅助表
Select
    a.Col1,COl2=substring(a.Col2,b.number,charindex(',',a.Col2+',',b.number)-b.number) 
from 
    Tab a join master..spt_values  b 
    ON B.type='p' AND B.number BETWEEN 1 AND LEN(A.col2)
where
     substring(','+a.COl2,b.number,1)=','


SQL2005用Xml:

select 
    a.COl1,b.Col2
from 
    (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
outer apply
    (select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b




SQL05用CTE:

;with roy as 
(select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
union all
select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
)
select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)

生成结果:
/*
Col1        COl2
----------- -----
1           a
1           b
1           c
2           d
2           e
3           f
*/

作者: fredrickhu 发布时间: 2011-12-06

照二楼的去动手做吧

作者: szstephenzhou 发布时间: 2011-12-06

SQL code


if object_id('a') is not null
   drop table a
go
create table a
(
 name varchar(10)
)
insert into a select '1,2,3,4'
go
if object_id('b') is not null
   drop table b
go
create table b
(
 name varchar(10)
)
insert into b select '1,4,6,7'
go
select t1.c1 from
(
select c1=substring(a.name,number,charindex(',',a.name+',',number)-number) from a cross join master..spt_values b where b.type='p' and number between 1 and len(a.name) and substring(','+a.name,number,1)=','
) t1 inner join 
(
select c1=substring(a.name,number,charindex(',',a.name+',',number)-number) from b a cross join master..spt_values b where b.type='p' and number between 1 and len(a.name) and substring(','+a.name,number,1)=','
) t2 on t1.c1=t2.c1
go
/*
c1
----------
1
4

(2 行受影响)
*/