问个sql语句
时间:2011-12-02
来源:互联网
现在数据库中的某个字段的数据是这样的
GENERATE
SUBMIT
APPROVE
APPROVAL_REJECT
SUBMIT
APPROVE
APPROVE
APPROVAL_REJECT
SUBMIT
APPROVE
APPROVE
APPROVE
我如何从最后一次SUBMIT开始取数据呢?(如上面,会取出最后四行)
GENERATE
SUBMIT
APPROVE
APPROVAL_REJECT
SUBMIT
APPROVE
APPROVE
APPROVAL_REJECT
SUBMIT
APPROVE
APPROVE
APPROVE
我如何从最后一次SUBMIT开始取数据呢?(如上面,会取出最后四行)
作者: yqsshr 发布时间: 2011-12-02
测试数据:
SQL code
结果:
SQL code
CREATE TABLE T29 ( ID VARCHAR2(20), des VARCHAR2(20) ); INSERT INTO T29 VALUES('1', 'GENERATE'); INSERT INTO T29 VALUES('2', 'SUBMIT'); INSERT INTO T29 VALUES('3', 'APPROVE'); INSERT INTO T29 VALUES('4', 'APPROVAL_REJECT'); INSERT INTO T29 VALUES('5', 'SUBMIT'); INSERT INTO T29 VALUES('6', 'APPROVE'); INSERT INTO T29 VALUES('7', 'APPROVE'); INSERT INTO T29 VALUES('8', 'APPROVAL_REJECT'); INSERT INTO T29 VALUES('9', 'SUBMIT'); INSERT INTO T29 VALUES('10', 'APPROVE'); INSERT INTO T29 VALUES('11', 'APPROVE'); INSERT INTO T29 VALUES('12', 'APPROVE');
结果:

作者: LuiseRADL 发布时间: 2011-12-02
巧妙运用自带的rowid,亮了
作者: xiedi1209 发布时间: 2011-12-02
SQL code
with t as ( select 'GENERATE' a from dual union all select 'SUBMIT' from dual union all select 'APPROVE' from dual union all select 'APPROVAL_REJECT' from dual union all select 'SUBMIT' from dual union all select 'APPROVE' from dual union all select 'APPROVE' from dual union all select 'APPROVAL_REJECT' from dual union all select 'SUBMIT' from dual union all select 'APPROVE' from dual union all select 'APPROVE' from dual union all select 'APPROVE' from dual ) select a from (select a,row_number() over (order by rownum) rn from t ) c where c.rn>= ( select max(rn) from ( select a,row_number() over (order by rownum) rn from t ) where a='SUBMIT' )
作者: dws2004 发布时间: 2011-12-02
额 跟1l的sql核心思想一样的
不过我加了row_numer排序,好像画蛇添足了
不过我加了row_numer排序,好像画蛇添足了
作者: dws2004 发布时间: 2011-12-02
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