求一条SQL语句,在线等~~
时间:2011-11-29
来源:互联网
ID UserID Add Quantity Price Remark
001 A mm 1 2 xxxx
002 A mm 1 2 xxxx
003 A mm 1 3 xxxx
004 B dd 2 2 xxxyy
005 C ww 1 2 ererr
006 B dd 1 3 34335
要得出以下结果:对于同一个UserID和Add的,就把ID用逗号连起来,并把他们的总金额Quantity * Price
ID UserID Add total Remark
001,002,003 A mm 7 xxxx
004,006 B dd 7 xxxyy
005 C ww 2 ererr
作者: lsp69 发布时间: 2011-11-29
select UserID,Add,total=sum(Price),max(remark), ID=stuff((select ','+id from tb where UserID=a.UserID and Add=a.Add for xml path('')),1,1,'') from tb a group by UserID,Add
作者: ssp2009 发布时间: 2011-11-29
合并列值 --******************************************************************************************* 表结构,数据如下: id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --============================================================================= create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + value FROM tb WHERE id=@id RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ --=================================================================================== 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */
作者: ssp2009 发布时间: 2011-11-29
合并列值 --******************************************************************************************* 表结构,数据如下: id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --============================================================================= create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + value FROM tb WHERE id=@id RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ --=================================================================================== 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
作者: fredrickhu 发布时间: 2011-11-29
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
这个方法,你只连接一列是可以解决,而且只能显示两列,但是我表要显示N列,但列的内容不同,我不是要所有列都group by
作者: lsp69 发布时间: 2011-11-29
select UserID,Add,total=sum(ISNULL(Price,0)),max(remark), ID=stuff((select ','+id from tb where UserID=a.UserID and Add=a.Add for xml path('')),1,1,'') from tb a group by UserID,Add
作者: t3121522520 发布时间: 2011-11-29
if object_id('tb','u') is not null drop table tb go create table tb ( id varchar(3), userid varchar(10), [add] varchar(10), quantity int, price int, remark varchar(10) ) go insert into tb select '001','A','mm',1,2,'xxxx' union all select '002','A','mm',1,2,'xxxx' union all select '003','A','mm',1,3,'xxxx' union all select '004','B','dd',2,2,'xxxyy' union all select '005','C','ww',1,2,'xxxyy' union all select '006','B','dd',1,3,'34335' go select id=stuff((select ','+ID from tb where UserID=a.userID for xml path('')),1,1,''),UserID,[Add],total=sum(quantity*price),remark=max(remark) from tb a group by UserID,[Add] go /* id UserID Add total remark ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- ---------- ---------- ----------- ---------- 004,006 B dd 7 xxxyy 001,002,003 A mm 7 xxxx 005 C ww 2 xxxyy (3 行受影响) */
作者: pengxuan 发布时间: 2011-11-29
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
要变成这样怎么写?表名字段名字段值都是变量
CREATE FUNCTION dbo.f_strUnite(@Table varchar(300),@Field varchar(300),@idField int,@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @s varchar(8000)
DECLARE @str varchar(8000)
SET @str = ''
set @s='SELECT ' + @str = @str + ',' + @Field + ' FROM ' + @Table + ' WHERE ' + @idField + '= ' + @id
RETURN STUFF(@str, 1, 1, '')
END
作者: lsp69 发布时间: 2011-11-29
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