怎样把这二条查询语句并成一条?
时间:2011-11-24
来源:互联网
不用join怎样把下面二条查询语句并成一条?
select bh,count(distinct kh) bs_j
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='1'
select bh,count(distinct kh) bs_d
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='2'
输出为:bh,bs_j,bs_d
select bh,count(distinct kh) bs_j
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='1'
select bh,count(distinct kh) bs_d
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='2'
输出为:bh,bs_j,bs_d
作者: sr_ljp 发布时间: 2011-11-24
洗洗睡吧.
作者: liangCK 发布时间: 2011-11-24
不好意思漏了group by bh
select bh,count(distinct kh) bs_j
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='1'
group by bh
select bh,count(distinct kh) bs_d
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='2'
group by bh
select bh,count(distinct kh) bs_j
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='1'
group by bh
select bh,count(distinct kh) bs_d
from tk_tab
where rq between '2011-09-01' and '2011-11-10' and bz='2'
group by bh
作者: sr_ljp 发布时间: 2011-11-24
SQL code
select bh,count(distinct kh) bs_j from tk_tab where rq between '2011-09-01' and '2011-11-10' and bz in('1','2') group by bh
作者: fredrickhu 发布时间: 2011-11-24
fredrickhu
谢谢!
bs_j是当bz='1'的结果,而bs_d是当bz='2'的结果.所以你提供的办法可能不行.
谢谢!
bs_j是当bz='1'的结果,而bs_d是当bz='2'的结果.所以你提供的办法可能不行.
作者: sr_ljp 发布时间: 2011-11-24
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