求一条SQL
时间:2011-10-24
来源:互联网
这种结果:
甲 乙 丙
A 1 0 0
B 2 11 11
C 1 1 1
D 1 1 1
要求?oracle和mysql都要
作者: mtv0199 发布时间: 2011-10-24
with T as (select 'a' a,'甲' b, '乙' c, '丙' d from dual union all select 'a','甲' b, '乙' c, '丙' d from dual union all select 'b','甲' b, '乙' c, '丙' d from dual union all select 'd','甲' b, '乙' c, '丙' d from dual union all select 'd','甲' b, '乙' c, '丙' d from dual union all select 'd','甲' b, '乙' c, '丙' d from dual union all select 'c','甲' b, '乙' c, '丙' d from dual union all select 'a','甲' b, '乙' c, '丙' d from dual union all select 'a','甲' b, '乙' c, '丙' d from dual union all select 'a','甲' b, '乙' c, '丙' d from dual )with T as
(select 'a' a,'甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
union all
select 'b','甲' b, '乙' c, '丙' d from dual
union all
select 'd','甲' b, '乙' c, '丙' d from dual
union all
select 'd','甲' b, '乙' c, '丙' d from dual
union all
select 'd','甲' b, '乙' c, '丙' d from dual
union all
select 'c','甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
)
select a,count(b),count(c),count(d) from T group by a[/code]
作者: cosio 发布时间: 2011-10-24
(select 'a' a,'甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
union all
select 'b','甲' b, '乙' c, '丙' d from dual
union all
select 'd','甲' b, '乙' c, '丙' d from dual
union all
select 'd','甲' b, '乙' c, '丙' d from dual
union all
select 'd','甲' b, '乙' c, '丙' d from dual
union all
select 'c','甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
union all
select 'a','甲' b, '乙' c, '丙' d from dual
)
select a,count(b) 甲,count(c) 乙,count(d) 丙 from T group by a[
---result:
a 5 5 5
b 1 1 1
c 1 1 1
d 3 3 3
/code]
作者: cosio 发布时间: 2011-10-24
作者: yixilan 发布时间: 2011-10-24
作者: hllfl 发布时间: 2011-10-24
from 商品表
group by 商品,商品类型,商品状态
order by 商品
作者: SKY_4K_PPM 发布时间: 2011-10-24
作者: coolkisses 发布时间: 2011-10-24
SELECT X.商品,X.C, Y.C, Z.C FROM (SELECT 商品,sum(数量) c where 状态 = '甲') X, (SELECT 商品,sum(数量) c where 状态 = '乙') Y, (SELECT 商品,sum(数量) c where 状态 = '丙') Z WHERE X.商品 = Y.商品 AND X.商品 = Z.商品 ;
作者: xiaobn_cn 发布时间: 2011-10-24
商品类型,
sum(decode(状态甲,1,0)) 状态甲,
sum(decode(状态乙,1,0)) 状态乙,
sum(decode(状态丙,1,0)) 状态丙
from 商品表
group by 商品类型;
作者: yds_512 发布时间: 2011-10-24
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