JSON嵌套对像如何填充JQuery datagrid控件
时间:2011-10-20
来源:互联网
{"total":2,"rows":["value":0,"department":{"depDesc":"技术部","depId":10,"depLevel":2,"depName":"产品与技术部","parentId":0,"path":"0.10.","version":null},"email":"[email protected]","empId":5,"enabled":true,"familyName":"超级管理员","firstKeyColumnName":"empId"}]}
如上面JSON对像,我现在要在JQuery的datagrid控件,显示department对像下面的depDesc属性值,应该怎样写代码呢,通过field:'department.depDesc' 都显示不了,直接填写field:'department'显示出来的是[Object Object]
如上面JSON对像,我现在要在JQuery的datagrid控件,显示department对像下面的depDesc属性值,应该怎样写代码呢,通过field:'department.depDesc' 都显示不了,直接填写field:'department'显示出来的是[Object Object]
作者: qfy2010 发布时间: 2011-10-20
var result={"total":2,"rows":["value":0,"department":{"depDesc":"技术部","depId":10,"depLevel":2,"depName":"产品与技术部","parentId":0,"path":"0.10.","version":null},"email":"[email protected]","empId":5,"enabled":true,"familyName":"超级管理员","firstKeyColumnName":"empId"}]} ;
var obj=eval("("+result+")");
var listobj=obj.rows;
listobj[1]['department'].depDesc;这样试试
var obj=eval("("+result+")");
var listobj=obj.rows;
listobj[1]['department'].depDesc;这样试试
作者: lihuan2008a 发布时间: 2011-10-20
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