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JSON嵌套对像如何填充JQuery datagrid控件

时间:2011-10-20

来源:互联网

{"total":2,"rows":["value":0,"department":{"depDesc":"技术部","depId":10,"depLevel":2,"depName":"产品与技术部","parentId":0,"path":"0.10.","version":null},"email":"[email protected]","empId":5,"enabled":true,"familyName":"超级管理员","firstKeyColumnName":"empId"}]} 
如上面JSON对像,我现在要在JQuery的datagrid控件,显示department对像下面的depDesc属性值,应该怎样写代码呢,通过field:'department.depDesc' 都显示不了,直接填写field:'department'显示出来的是[Object Object]

作者: qfy2010   发布时间: 2011-10-20

var result={"total":2,"rows":["value":0,"department":{"depDesc":"技术部","depId":10,"depLevel":2,"depName":"产品与技术部","parentId":0,"path":"0.10.","version":null},"email":"[email protected]","empId":5,"enabled":true,"familyName":"超级管理员","firstKeyColumnName":"empId"}]} ;

var obj=eval("("+result+")");
var listobj=obj.rows;
listobj[1]['department'].depDesc;这样试试

作者: lihuan2008a   发布时间: 2011-10-20

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