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Ajax如何调用后台php代码访问数据库

时间：2011-10-18

来源：互联网

Ajax如何调用数据库，这里我用的JS代码是function check{
var xmlHttp

function showUser(str)
{
xmlHttp=GetXmlHttpObject()
if (xmlHttp==null)
{
alert ("Browser does not support HTTP Request")
return
}
var url="getuser.php" //getuser.php是我的PHP文件，功能是链接数据库并且访问
xmlHttp.onreadystatechange=stateChanged
xmlHttp.open("GET",url,true)
xmlHttp.send(null)
}

function stateChanged()
{
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
{
document.getElementById("txtHint").innerHTML=xmlHttp.responseText
}
}

function GetXmlHttpObject()
{
var xmlHttp=null;
try
{
// Firefox, Opera 8.0+, Safari
xmlHttp=new XMLHttpRequest();
}
catch (e)
{
//Internet Explorer
try
{
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e)
{
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
}
return xmlHttp;
}

}
php代码是：<?php

//连接数据库的函数
$con = mysql_connect('localhost', 'root', '123');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("storage", $con);

$sql="SELECT * FROM user_main";

$result = mysql_query($sql);

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
</tr>";

while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['user_id'] . "</td>";
echo "<td>" . $row['user_name'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['text'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysql_close($con);
?>
html代码是：<html>
<head>
<script src="selectuser.js"></script>
</head>
<body>

<form method="post" onSubmit="return showUser();">
Select a User:
<input type="submit" name="users" value="提交" >

</form>
<p>
<div><b>User info will be listed here.</b></div>
</p>

</body>
</html>
求各位大侠指教

作者: wshiwushengzhong 发布时间: 2011-10-18

急。。。！求大侠帮帮我，我会后续加分的

作者: wshiwushengzhong 发布时间: 2011-10-18