extjs 高分求救，在线等

不多说直接上代码
//编辑角色
var editRole = function() {

var selectedRecord = grid.getSelectionModel().getSelected();

if(!selectedRecord) {
Ext.Msg.alert("提示", "请选择要编辑的行！");
return;
} else {
var updateWin = createFormPanel("角色编辑", "role/role_update.action");
updateWin.getComponent(0).getForm().loadRecord(selectedRecord);

}

};

//创建formPanel
var createFormPanel = function(title, url) {

var win = new Ext.Window({
id:"win",
title:title,
width:300,
height:200
});

var formPanel = new Ext.form.FormPanel({

labelWidth:60,
buttons:[{
text:"保存",
handler:function(){
formPanel.getForm().submit({
url:url,
success:function(form, action) {
Ext.Msg.alert("success", "角色保存成功！");
jsonStore.reload();
win.close();
}

});

}
},{
text:"重置",
handler:function(){
formPanel.form.reset();

}
}],
items:[{
xtype:"hidden",
name:"role.id"
// name:"id"
},{
xtype:"textfield",
fieldLabel:"角色名",
allowBlank:false,
blankText:"不允许为空！",
name:"role.roleName"
// name:"roleName"

},{
xtype:"textarea",
fieldLabel:"角色描述",
anchor:"-80",
name:"role.roleDesc"
// name:"roleDesc"
},{
xtype:"hidden",
name:"role.insertTime"
// name:"insertTime"
}]

});

win.add(formPanel);
win.show();

return win;
};
我想弹出修改的窗口上加载选中记录的信息，textfield或textarea的name属性只有用“role.*”就不行，去掉role才行。但我action的要求参数是role.*才能获取到，请各位高手指教！！急!

http://happyran.zbpifa.com
http://007ej.com/user.asp