MapView 的 getFromLocationName, 模糊范围的搜寻

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public class MapUtility {
  public static JSONObject getLocationInfo(String address) {
 
    HttpGet httpGet = new HttpGet("http://maps.google."
 
    + "com/maps/api/geocode/json?address=" + address
 
    + "&sensor=false");
 
    HttpClient client = new DefaultHttpClient();
 
    HttpResponse response;
 
    StringBuilder stringBuilder = new StringBuilder();
 
    try {
 
      response = client.execute(httpGet);
 
      HttpEntity entity = response.getEntity();
 
      InputStream stream = entity.getContent();
 
      int b;
 
      while ((b = stream.read()) != -1) {
 
        stringBuilder.append((char) b);
 
      }
 
    } catch (ClientProtocolException e) {
 
      e.printStackTrace();
 
    } catch (IOException e) {
 
      e.printStackTrace();
 
    }
 
    JSONObject jsonObject = new JSONObject();
 
    try {
 
      jsonObject = new JSONObject(stringBuilder.toString());
 
    } catch (JSONException e) {
 
      e.printStackTrace();
 
    }
 
    return jsonObject;
 
  }
 
  // converts JSONObject into a GeoPoint.
 
  public static GeoPoint getGeoPoint(JSONObject jsonObject) {
 
    Double lon = new Double(0);
 
    Double lat = new Double(0);
 
    try {
 
      lon = ((JSONArray) jsonObject.get("results")).getJSONObject(0)
 
      .getJSONObject("geometry").getJSONObject("location")
 
      .getDouble("lng");
 
      lat = ((JSONArray) jsonObject.get("results")).getJSONObject(0)
 
      .getJSONObject("geometry").getJSONObject("location")
 
      .getDouble("lat");
 
    } catch (JSONException e) {
 
      e.printStackTrace();
 
    }
 
    return new GeoPoint((int) (lat * 1E6), (int) (lon * 1E6));
 
  }
}