关于Mysql多列同时汇总的问题。急~~~
时间:2011-08-03
来源:互联网
目前遇到一个这样的问题,关于同时显示多列汇总的问题。请高手帮忙看看。谢谢。急!~~
数据库记录如下:
mydate | mysite | mystat
-------------------------------------
2011-08-03 | 网点1 | 0
2011-08-03 | 网点2 | 1
2011-08-03 | 网点2 | 1
2011-08-03 | 网点1 | 0
2011-08-03 | 网点1 | 1
2011-08-03 | 网点2 | 0
2011-08-03 | 网点1 | 1
2011-08-03 | 网点1 | 1
2011-08-03 | 网点2 | 0
2011-08-03 | 网点2 | 0
我想显示出如下汇总信息:
mydate | mysite | count(mystat(0)) | count(mystat(1))
2011-08-03 | 网点1 | 2 | 3
2011-08-03 | 网点2 | 3 | 2
数据库记录如下:
mydate | mysite | mystat
-------------------------------------
2011-08-03 | 网点1 | 0
2011-08-03 | 网点2 | 1
2011-08-03 | 网点2 | 1
2011-08-03 | 网点1 | 0
2011-08-03 | 网点1 | 1
2011-08-03 | 网点2 | 0
2011-08-03 | 网点1 | 1
2011-08-03 | 网点1 | 1
2011-08-03 | 网点2 | 0
2011-08-03 | 网点2 | 0
我想显示出如下汇总信息:
mydate | mysite | count(mystat(0)) | count(mystat(1))
2011-08-03 | 网点1 | 2 | 3
2011-08-03 | 网点2 | 3 | 2
作者: jxflll 发布时间: 2011-08-03
没有人会吗?自己顶。急,在线等。
作者: jxflll 发布时间: 2011-08-03
select mydate,mysite
,sum(case when mystat=0 then 1 end) as 'count(mystat(0))'
,sum(case when mystat=1 then 1 end) as 'count(mystat(1))'
from tb
group by mydate,mysite
,sum(case when mystat=0 then 1 end) as 'count(mystat(0))'
,sum(case when mystat=1 then 1 end) as 'count(mystat(1))'
from tb
group by mydate,mysite
作者: rucypli 发布时间: 2011-08-03
select mydate,mysite,
sum(1-mystat) as `count(mystat(0))`,
sum(mystat) as `count(mystat(1))`
from 数据库记录如下
group by mydate,mysite
sum(1-mystat) as `count(mystat(0))`,
sum(mystat) as `count(mystat(1))`
from 数据库记录如下
group by mydate,mysite
作者: ACMAIN_CHM 发布时间: 2011-08-03
引用 2 楼 rucypli 的回复:
select mydate,mysite
,sum(case when mystat=0 then 1 end) as 'count(mystat(0))'
,sum(case when mystat=1 then 1 end) as 'count(mystat(1))'
from tb
group by mydate,mysite
select mydate,mysite
,sum(case when mystat=0 then 1 end) as 'count(mystat(0))'
,sum(case when mystat=1 then 1 end) as 'count(mystat(1))'
from tb
group by mydate,mysite
高手!谢谢!
作者: jxflll 发布时间: 2011-08-03
引用 3 楼 acmain_chm 的回复:
select mydate,mysite,
sum(1-mystat) as `count(mystat(0))`,
sum(mystat) as `count(mystat(1))`
from 数据库记录如下
group by mydate,mysite
select mydate,mysite,
sum(1-mystat) as `count(mystat(0))`,
sum(mystat) as `count(mystat(1))`
from 数据库记录如下
group by mydate,mysite
这个没太懂。能解释下吗?谢谢。
作者: jxflll 发布时间: 2011-08-03
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