为什么我返回的值是“0”?
时间:2011-08-03
来源:互联网
If zx - 10 ^ 12 < 0 Then
jiang = "自选错误"
End If
Exit Function
If zj - 10 ^ 12 < 0 Then
jiang = "中奖号错误"
End If
Exit Function
Dim r(6) As Single
Dim jr(6) As Single
Dim b, jb, p, i, j
p = 0
For i = 1 To 6
For j = 1 To 6
If r(i) = jr(j) Then
p = p + 1
End If
Next j
Next i
r(i) = (zx Mod 10 ^ (8 - i) - zx Mod 10 ^ (7 - i)) / 10 ^ (7 - i)
b = zx Mod 10 ^ 2
jr(i) = (zj Mod 10 ^ (8 - i) - zj Mod 10 ^ (7 - i)) / 10 ^ (7 - i)
jb = zj Mod 10 ^ 2
If r(i) = jr(i) Then
p = p + 1
End If
If b = jb Then
If p = 6 Then
jiang = "一等奖"
ElseIf p = 5 Then
jiang = "三等奖"
ElseIf p = 4 Then
jiang = "四等奖"
ElseIf p = 3 Then
jiang = "五等奖"
ElseIf p < 3 Then
jiang = "六等奖"
End If
Else
If p = 6 Then
jiang = "二等奖"
ElseIf p = 5 Then
jiang = "四等奖"
ElseIf p = 4 Then
jiang = "五等奖"
ElseIf p < 4 Then
jiang = "未中奖"
End If
End If
End Function
作者: cslaoyuweng 发布时间: 2011-08-03
作者: BestBadGod 发布时间: 2011-08-03
作者: BestBadGod 发布时间: 2011-08-03
作者: cslaoyuweng 发布时间: 2011-08-03
Exit Function
End If
If zj - 10 ^ 12 < 0 Then
jiang = "中奖号错误"
Exit Function
End If
Dim r(6) As Single
Dim jr(6) As Single
Dim b, jb, p, i, j
For i = 1 To 6
For j = 1 To 6
Next j
Next i
r(i) = (zx Mod 10 ^ (2 * (8 - i)) - (zx Mod 10 ^ (2 * (7 - i)))) / 10 ^ ((7 - i) * 2)
jr(j) = (zj Mod 10 ^ (2 * (8 - i)) - (zj Mod 10 ^ (2 * (7 - i)))) / 10 ^ ((7 - i) * 2)
If r(i) = jr(j) Then
p = 0
p = p + 1
End If
b = zx Mod 10 ^ 2
jb = zj Mod 10 ^ 2
If b = jb Then
If p = 6 Then
jiang = "一等奖"
ElseIf p = 5 Then
jiang = "三等奖"
ElseIf p = 4 Then
jiang = "四等奖"
ElseIf p = 3 Then
jiang = "五等奖"
ElseIf p < 3 Then
jiang = "六等奖"
End If
Else
If p = 6 Then
jiang = "二等奖"
ElseIf p = 5 Then
jiang = "四等奖"
ElseIf p = 4 Then
jiang = "五等奖"
ElseIf p < 4 Then
jiang = "未中奖"
End If
End If
End Function
作者: cslaoyuweng 发布时间: 2011-08-03
If zx - 10 ^ 12 < 0 Then
jiang = "自选错误"
Exit Function
End If
If zj - 10 ^ 12 < 0 Then
jiang = "中奖号错误"
Exit Function
End If
Dim r(6) As Single
Dim jr(6) As Single
Dim b, jb, p, i, j
For i = 1 To 6
For j = 1 To 6
r(i) = (zx Mod 10 ^ (2 * (8 - i)) - (zx Mod 10 ^ (2 * (7 - i)))) / 10 ^ ((7 - i) * 2)
jr(j) = (zj Mod 10 ^ (2 * (8 - i)) - (zj Mod 10 ^ (2 * (7 - i)))) / 10 ^ ((7 - i) * 2)
If r(i) = jr(j) Then p = p + 1
Next j
Next i
b = zx Mod 10 ^ 2
jb = zj Mod 10 ^ 2
If b = jb Then
If p = 6 Then
jiang = "一等奖"
ElseIf p = 5 Then
jiang = "三等奖"
ElseIf p = 4 Then
jiang = "四等奖"
ElseIf p = 3 Then
jiang = "五等奖"
ElseIf p < 3 Then
jiang = "六等奖"
End If
Else
If p = 6 Then
jiang = "二等奖"
ElseIf p = 5 Then
jiang = "四等奖"
ElseIf p = 4 Then
jiang = "五等奖"
ElseIf p < 4 Then
jiang = "未中奖"
End If
End If
End Function
作者: cslaoyuweng 发布时间: 2011-08-03
作者: wju200510 发布时间: 2011-08-03
作者: BestBadGod 发布时间: 2011-08-03
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