ajax的getjson()读取
时间:2011-06-14
来源:互联网
怎样用ajax的getjson()读取这段json里的信息??谢谢~
var folderTreeJson = {"data":{"1":{"name":"公司文档","aid":"1","pid":"0","msg":"10"},
"2":{"name":"文档","aid":"2","pid":"0","msg":"0"},
"3":{"name":"共享","aid":"3","pid":"0","msg":"0"},
"11":{"name":"规章制度","aid":"11","pid":"1","share":"0","msg":"10"},
"111":{"name":"考核制度","aid":"111","pid":"1","share":"1","msg":"0"},
"1111":{"name":"临时文件夹","aid":"1111","pid":"111","share":"1","msg":"10
}
}
var newTreeNodeJson = {"data":{"22":{"name":"我的图片","aid":"22","pid":"1111","msg":"0"}}};
var newTreeNodeJson2 = {"data":{"22":{"name":"图片","aid":"22","pid":"1111","msg":"10","share":"1"}}};
var newTreeNodeJson1 = {"data":{"33":{"name":"毛线","aid":"33","pid":"22","msg":"0"}}};
var folderTreeJson = {"data":{"1":{"name":"公司文档","aid":"1","pid":"0","msg":"10"},
"2":{"name":"文档","aid":"2","pid":"0","msg":"0"},
"3":{"name":"共享","aid":"3","pid":"0","msg":"0"},
"11":{"name":"规章制度","aid":"11","pid":"1","share":"0","msg":"10"},
"111":{"name":"考核制度","aid":"111","pid":"1","share":"1","msg":"0"},
"1111":{"name":"临时文件夹","aid":"1111","pid":"111","share":"1","msg":"10
}
}
var newTreeNodeJson = {"data":{"22":{"name":"我的图片","aid":"22","pid":"1111","msg":"0"}}};
var newTreeNodeJson2 = {"data":{"22":{"name":"图片","aid":"22","pid":"1111","msg":"10","share":"1"}}};
var newTreeNodeJson1 = {"data":{"33":{"name":"毛线","aid":"33","pid":"22","msg":"0"}}};
作者: lironghai123 发布时间: 2011-06-14
因该是jquery的getJson吧。。。ajax没有getJson这个方法
你直接用script标签加载包含json变量的文件不就行了??
这些内容不符合json格式的定义,如果一定要ajax动态加载,是用eval来生成对应的json对象,并且不能是用var声明变量,要不eval后是局部变量了
你直接用script标签加载包含json变量的文件不就行了??
这些内容不符合json格式的定义,如果一定要ajax动态加载,是用eval来生成对应的json对象,并且不能是用var声明变量,要不eval后是局部变量了
作者: showbo 发布时间: 2011-06-14
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