grep 给数组赋值

cat my.log
Date:  1 sajdlkfjsakdj
asdkjflksjdf
Date:  2312jlkjklj123
sdfjslkdjf
Date:  asdfjlsajdkfjslkjdf

同过一条命令，给数组l赋值，通过${#l[@]} 大小，通过${l[@]}输出所有数组，
l=$(grep -Enr "Date: " my.log  ) ; echo ${#l[@]} "============" ${l[@]}  "-------" ${l[0]}

Output:
3 ========== Date:  1 sajdlkfjsakdj
Date:  2312jlkjklj123
Date:  asdfjlsajdkfjslkjdf
------------------ Date:  1 sajdlkfjsakdj

l=($(grep -Enr "Date: " my.log  )) ; echo ${#l[@]} "============" ${l[@]}  "-------" ${l[0]}


解决