首页 手机软件 手机游戏 单机游戏 资讯文章 专题下载 游戏合集 文章合集 php下载 php教程 电脑软件
+ -
当前位置：首页 → 问答吧 → 一个疑问

一个疑问

时间：2010-12-11

来源：互联网

本帖最后由 eeeee159963 于 2010-12-11 19:09 编辑
  1. # Credit inquiry program.

  3. import sys

  5. # retrieve one user command
  6. def getRequest():
  7.    
  8.    while 1:
  9.       request = int( raw_input( "\n? " ) )
  10.      
  11.       if 1 <= request <= 4:
  12.          break

  14.    return request

  16. # determine if balance should be displayed, based on type
  17. def shouldDisplay( accountType, balance ):

  19.    if accountType == 2 and balance < 0:     # credit balance
  20.       return 1

  22.    elif accountType == 3 and balance > 0:   # debit balance
  23.       return 1

  25.    elif accountType == 1 and balance == 0:  # zero balance
  26.       return 1

  28.    else: return 0

  30. # print formatted balance data
  31. def outputLine( account, name, balance ):
  32.    
  33.    print account.ljust( 10 ),
  34.    print name.ljust( 10 ),
  35.    print balance.rjust( 10 )

  37. # open file
  38. try:
  39.    file = open( "clients.dat", "r" )
  40. except IOError:
  41.    print >> sys.stderr, "File could not be opened"
  42.    sys.exit( 1 )

  44. print "Enter request"
  45. print "1 - List accounts with zero balances"
  46. print "2 - List accounts with credit balances"
  47. print "3 - List accounts with debit balances"
  48. print "4 - End of run"

  50. # process user request(s)
  51. while 1:

  53.    request = getRequest()   # get user request

  55.    if request == 1:         # zero balances
  56.       print "\nAccounts with zero balances:"
  57.    elif request == 2:       # credit balances
  58.       print "\nAccounts with credit balances:"
  59.    elif request == 3:       # debit balances
  60.       print "\nAccounts with debit balances:"
  61.    elif request == 4:       # exit loop
  62.       break
  63.    else:  # getRequest should never let program reach here
  64.       print "\nInvalid request."

  66.    currentRecord = file.readline()    # get first record

  68.    # process each line
  69.    while ( currentRecord != "" ):
  70.       account, name, balance = currentRecord.split()
  71.       balance = float( balance )
  72.       
  73.       if shouldDisplay( request, balance ):
  74.          outputLine( account, name, str( balance ) )

  76.       currentRecord = file.readline() # get next record

  78.    file.seek( 0, 0 )                  # move to beginning of file
  79.   
  80. print "\nEnd of run."
  81. file.close()                          # close file

  83.                                              
复制代码


第51行的while循环结束条件是什么

作者: eeeee159963   发布时间: 2010-12-11

elif request == 4:       # exit loop
      break

作者: catcat811   发布时间: 2010-12-11

相关阅读 更多

热门阅读

热门下载

更多
关于本站 免责申明 联系我们

Copyright 2006-2020 php爱好者(phpfans.net) All Rights Reserved.备案号：湘ICP备2023016114号-2

本站为非盈利性网站，不接受任何广告。本站所有资源均由网友上传，如有侵权，请发邮件至 [email protected] phpfans.net