+ -
当前位置:首页 → 问答吧 → Perl CGI 写文件严重灵异了,求助ing

Perl CGI 写文件严重灵异了,求助ing

时间:2010-11-06

来源:互联网

代码是这样的
  1.     open (SPRINT, ">${project}/data/sprint_plan.csv" ) || die "cannot write to file ";
  2.     $num = 0;
  3.     foreach (@start_date) {
  4. #        print "end_date = $_ <br>";
  5. #        print join "|", $start_date[$num], $end_date[$num], $num+1, "<br>";

  6.         print "start date = $_ <br>";
  7.         $end = $end_date[$num];
  8.        
  9. #        $sprint_plan = join ",", $num+1, $_, $end_date[$num] ;
  10. #        $sprint_plan = join "|",  $_, $num++ ;
  11.         print "end date = $end<br>";
  12.         print SPRINT "$_ | ";
  13.         print SPRINT "$end | ";
  14.         print SPRINT $num++, "\n"
  15. #        print SPRINT "$_|$start|<br>\n";
  16. #        print SPRINT "----------------\n";
  17. #        $num++;
  18.     }
  19.     close (SPRINT);
复制代码
执行之后页面输出这样的信息
  1. start date = 2010-03-04
  2. end date = 2010-03-14
  3. start date = 2010-03-15
  4. end date = 2010-03-25
  5. start date = 2010-03-26
  6. end date = 2010-04-05
  7. start date = 2010-04-06
  8. end date = 2010-04-18
  9. start date = 2010-04-19
  10. end date = 2010-04-27
  11. start date = 2010-04-28
  12. end date = 2010-05-08
  13. start date = 2010-05-09
  14. end date = 2010-05-19
  15. start date = 2010-05-20
  16. end date = 2010-05-30
  17. start date = 2010-05-31
  18. end date = 2010-06-10
  19. start date = 2010-06-11
  20. end date =
复制代码
但灵异的是文件始终是这样的结果
  1. -bash-3.1# cat /var/www/cgi-bin/new/data/sprint_plan.csv
  2. | 0
  3. | 1
  4. | 2
  5. | 3
  6. | 4
  7. | 5
  8. | 6
  9. | 7
  10. | 8
  11. 2010-06-11 |  | 9
  12. -bash-3.1#
复制代码
灵异的是,如果把这一行注释掉
  1. #        print SPRINT "$end | ";
复制代码
, 就会成这样的结果
  1. -bash-3.1# cat /var/www/cgi-bin/new/data/sprint_plan.csv
  2. 2010-03-04 | 0
  3. 2010-03-15 | 1
  4. 2010-03-26 | 2
  5. 2010-04-06 | 3
  6. 2010-04-19 | 4
  7. 2010-04-28 | 5
  8. 2010-05-09 | 6
  9. 2010-05-20 | 7
  10. 2010-05-31 | 8
  11. 2010-06-11 | 9
  12. -bash-3.1#
复制代码

作者: dove-young   发布时间: 2010-11-06

如果把 这一行换成其他任何变量,都能成功写入文件
  1. #        print SPRINT "$end | ";
复制代码
换成
  1. #        print SPRINT "$start | ";
复制代码
,就能成功写入
  1. -bash-3.1# cat /var/www/cgi-bin/new/data/sprint_plan.csv
  2. 2010-03-04 | 2010-03-04 | 0
  3. 2010-03-15 | 2010-03-04 | 1
  4. 2010-03-26 | 2010-03-04 | 2
  5. 2010-04-06 | 2010-03-04 | 3
  6. 2010-04-19 | 2010-03-04 | 4
  7. 2010-04-28 | 2010-03-04 | 5
  8. 2010-05-09 | 2010-03-04 | 6
  9. 2010-05-20 | 2010-03-04 | 7
  10. 2010-05-31 | 2010-03-04 | 8
  11. 2010-06-11 | 2010-03-04 | 9
  12. -bash-3.1#
复制代码

作者: dove-young   发布时间: 2010-11-06

看起来真是相当奇怪。 print $end 输出到 STDOUT 没任何问题,可是为什么就是写不到文件呢? 而且还是只要包括了他, $start_date 也写不进去了

作者: dove-young   发布时间: 2010-11-06

本帖最后由 zhlong8 于 2010-11-07 00:22 编辑

无法重现你的错误

copy的你的代码,加了点数据,一切正常。

作者: zhlong8   发布时间: 2010-11-07