根据经纬度坐标计算实际距离
时间:2010-10-21
来源:互联网
- double hypot(double x, double y) {
- return sqrt(x * x + y * y);
- }
-
- double distance(double wd1, double jd1, double wd2, double jd2) {// 根据经纬度坐标计算实际距离
- double x, y, out;
- double PI = 3.1415926535898;
- double R = 6.371229 * 1e6;
- x = (jd2 - jd1) * PI * R * cos( ( (wd1 + wd2) / 2) * PI / 180) / 180;
- y = (wd2 - wd1) * PI * R / 180;
- out = hypot(x, y);
- return out;
- }
http://blog.csdn.net/zgl_dm/archive/2007/11/23/1899598.aspx
作者: 醒目 发布时间: 2010-10-21
QUOTE:
[root@localhost ]# perl 1.pl
101.36658837807
[root@localhost ]# cat 1.pl
#!/bin/perl
#
my $JuLi= &distance(116.41794,39.99347,116.41787,39.99256);#$wd1, $jd1, $wd2, $jd2
print "$JuLi \n";
sub distance() {
my ($wd1, $jd1, $wd2, $jd2);
$wd1=$_[1];
$jd1=$_[0];
$wd2=$_[3];
$jd2=$_[2];
my $PI=3.1415926535898;
my $R = 6.371229 * 1e6;
#print "$R \n";
$x = ($jd2 - $jd1) * $PI * $R * cos( ( ($wd1 + $wd2) / 2) * $PI / 180) / 180;
$y = ($wd2 - $wd1) * $PI * $R / 180;
my $temp = sqrt($x * $x + $y * $y);
return $temp;
}
101.36658837807
[root@localhost ]# cat 1.pl
#!/bin/perl
#
my $JuLi= &distance(116.41794,39.99347,116.41787,39.99256);#$wd1, $jd1, $wd2, $jd2
print "$JuLi \n";
sub distance() {
my ($wd1, $jd1, $wd2, $jd2);
$wd1=$_[1];
$jd1=$_[0];
$wd2=$_[3];
$jd2=$_[2];
my $PI=3.1415926535898;
my $R = 6.371229 * 1e6;
#print "$R \n";
$x = ($jd2 - $jd1) * $PI * $R * cos( ( ($wd1 + $wd2) / 2) * $PI / 180) / 180;
$y = ($wd2 - $wd1) * $PI * $R / 180;
my $temp = sqrt($x * $x + $y * $y);
return $temp;
}
作者: 枫影谁用了 发布时间: 2010-10-21
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