请教 Popup 问题

想 Show 2 个 POPUP, one after one, 但现在只能show第一个 (doPopUP), 不能show callback_1, 应点改?

* Photo Slider Init --- START
*/
var dummy = function(){};

var callback_1 = function () {
$('#popupPage2').fancybox({ :460, :400, : false, : 'iframe', : function(currentArray, currentIndex, currentOpts){ setTimeout(dummy ,currentOpts.speedOut); } }).click(); };

var doPopUp = function () {
$('#popupPage1').fancybox({ :820, :600, : false, : 'iframe', : function(currentArray, currentIndex, currentOpts){ setTimeout(dummy,currentOpts.speedOut); } }).click(); };

$(document).ready(function() {
$('.slider').s3Slider({
timeOut: 6000
});
doPopUp(); callback_1(); });
/**
* Photo Slider Init --- END
*/
</script>
<div style="display: none;"> <a id="popupPage1" href="popup_en.html">Popup Hidden Link</a></div>
<div style="display: none;"> <a id="popupPage2" href="popup_facebook.html">Popup Hidden Link</a></div>

请upload source code file.

你咁样梗系唔得啦
fancybox 同一时间只可出一个
可以考虑用 jquery ui ge dialog, 出无限个都得